• Thumbnail for Ultrafilter
    In the mathematical field of order theory, an ultrafilter on a given partially ordered set (or "poset") P {\textstyle P} is a certain subset of P , {\displaystyle...
    20 KB (2,956 words) - 14:53, 25 July 2024
  • Thumbnail for Ultrafilter on a set
    In the mathematical field of set theory, an ultrafilter on a set X {\displaystyle X} is a maximal filter on the set X . {\displaystyle X.} In other words...
    47 KB (7,377 words) - 04:20, 9 April 2024
  • Thumbnail for Almost everywhere
    property true almost everywhere is sometimes defined in terms of an ultrafilter. An ultrafilter on a set X is a maximal collection F of subsets of X such that:...
    9 KB (1,261 words) - 12:11, 1 July 2024
  • ideals. A variation of this statement for filters on sets is known as the ultrafilter lemma. Other theorems are obtained by considering different mathematical...
    15 KB (2,257 words) - 03:04, 29 November 2023
  • Thumbnail for Hyperreal number
    be extended to an ultrafilter, but the proof uses the axiom of choice. The existence of a nontrivial ultrafilter (the ultrafilter lemma) can be added...
    33 KB (4,899 words) - 05:38, 27 September 2024
  • principal ultrafilter on X {\displaystyle X} . Moreover, every principal ultrafilter on X {\displaystyle X} is necessarily of this form. The ultrafilter lemma...
    6 KB (835 words) - 07:05, 15 October 2024
  • to the following criterion: assuming the ultrafilter lemma, a space is compact if and only if each ultrafilter on the space converges. With this in hand...
    15 KB (2,098 words) - 09:49, 19 July 2024
  • configurations in the X n {\displaystyle X_{n}} spaces employing an ultrafilter to bypass the need for repeated consideration of subsequences to ensure...
    14 KB (2,462 words) - 09:48, 17 May 2024
  • element i ∈ I {\displaystyle i\in I} (all of the same signature), and an ultrafilter U {\displaystyle {\mathcal {U}}} on I . {\displaystyle I.} For any two...
    18 KB (3,108 words) - 20:35, 16 August 2024
  • Thumbnail for Boolean algebra (structure)
    ultrafilter is called the ultrafilter lemma and cannot be proven in Zermelo–Fraenkel set theory (ZF), if ZF is consistent. Within ZF, the ultrafilter...
    49 KB (3,356 words) - 02:25, 17 September 2024
  • then the ultrafilter U witnessing that κ is measurable will be in Vκ+2 and thus in M. So for any α < κ, we have that there exist an ultrafilter U in j(Vκ)...
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  • million 2002 - Acquired industrial parts maker Ultrafilter International AG for $68 million. Ultrafilter had sales of $100 million and operated in 30 countries...
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  • Countable Uncountable Empty Inhabited Singleton Finite Infinite Transitive Ultrafilter Recursive Fuzzy Universal Universe constructible Grothendieck Von Neumann...
    2 KB (338 words) - 06:16, 4 March 2024
  • the set of all ultrafilters on X , {\displaystyle X,} with the elements of X {\displaystyle X} corresponding to the principal ultrafilters. The topology...
    21 KB (2,917 words) - 20:19, 2 October 2024
  • characterizations of "ultrafilter" and "ultra prefilter," which are listed in the article on ultrafilters. Important properties of ultrafilters are also described...
    138 KB (23,262 words) - 13:33, 19 September 2024
  • Thumbnail for Axiom of choice
    former is equivalent in ZF to Tarski's 1930 ultrafilter lemma: every filter is a subset of some ultrafilter. One of the most interesting aspects of the...
    58 KB (7,685 words) - 22:21, 12 November 2024
  • σ-centered set Net (mathematics) Upper set and lower set Ideal and filter Ultrafilter Completeness (order theory) Dense order Distributivity (order theory)...
    5 KB (396 words) - 12:14, 30 October 2023
  • Thumbnail for Filters in topology
    to a point or a set, and many others. Special types of filters called ultrafilters have many useful technical properties and they may often be used in place...
    192 KB (30,860 words) - 18:47, 6 November 2024
  • } However, an ultrafilter (and any other non-degenerate filter) is free if and only if it includes the Fréchet filter. The ultrafilter lemma states that...
    6 KB (932 words) - 09:40, 9 August 2024
  • where the property holds is a member of the ultrafilter, i.e. has measure 1.) Also equivalent, the ultrafilter (set of sets of measure 1) is closed under...
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  • Thumbnail for Gödel's completeness theorem
    provably equivalent to a weak form of the axiom of choice known as the ultrafilter lemma. In particular, no theory extending ZF can prove either the completeness...
    17 KB (2,329 words) - 23:58, 17 October 2024
  • filter F {\displaystyle {\mathcal {F}}} on X {\displaystyle X} is an ultrafilter if, for every A ⊆ X , {\displaystyle A\subseteq X,} either A ∈ F {\displaystyle...
    11 KB (2,060 words) - 08:08, 28 April 2024
  • Thumbnail for Filter (mathematics)
    dual to a filter is an order ideal. Special cases of filters include ultrafilters, which are filters that cannot be enlarged, and describe nonconstructive...
    23 KB (2,819 words) - 18:40, 14 October 2024
  • Y} has a neighborhood on which f {\displaystyle f} is constant. Every ultrafilter U {\displaystyle {\mathcal {U}}} on a non-empty set X {\displaystyle...
    15 KB (2,287 words) - 15:02, 11 November 2024
  • proving that certain perfect sets are uncountable, and the construction of ultrafilters. Let X {\textstyle X} be a set and A {\textstyle {\mathcal {A}}} a nonempty...
    17 KB (2,667 words) - 13:37, 4 October 2024
  • Countable Uncountable Empty Inhabited Singleton Finite Infinite Transitive Ultrafilter Recursive Fuzzy Universal Universe constructible Grothendieck Von Neumann...
    92 KB (12,121 words) - 18:52, 8 November 2024
  • direction, a Boolean algebra A {\displaystyle A} has a unique non-principal ultrafilter (that is, a maximal filter not generated by a single element of the algebra)...
    6 KB (884 words) - 17:19, 18 February 2024
  • size κ with A ∈ M, and a nonprincipal ultrafilter U on the Boolean algebra P(κ) ∩ M such that: U is an M-ultrafilter: for any sequence ⟨Xβ : β < κ⟩ ∈ M of...
    4 KB (550 words) - 10:12, 26 July 2024
  • cofinalities that occur if we consider all ultrafilters on A, that is, pcf ⁡ ( A ) = { cf ⁡ ( ∏ A / D ) : D is an ultrafilter on A } . {\displaystyle \operatorname...
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  • choice, the uniqueness of the cardinality of the basis requires only the ultrafilter lemma, which is strictly weaker (the proof given below, however, assumes...
    6 KB (780 words) - 22:18, 8 February 2024