geometry, the semiperimeter of a polygon is half its perimeter. Although it has such a simple derivation from the perimeter, the semiperimeter appears frequently...

⁠ ⁠ c . {\displaystyle c.} ⁠ Letting ⁠ s {\displaystyle s} ⁠ be the semiperimeter of the triangle, s = 1 2 ( a + b + c ) , {\displaystyle s={\tfrac {1}{2}}(a+b+c)...

− d ) {\displaystyle K={\sqrt {(s-a)(s-b)(s-c)(s-d)}}} where s, the semiperimeter, is defined to be s = a + b + c + d 2 . {\displaystyle s={\frac {a+b+c+d}{2}}...

{\displaystyle \triangle ABC} with sides a ≤ b < c {\displaystyle a\leq b<c} , semiperimeter s = 1 2 ( a + b + c ) {\textstyle s={\tfrac {1}{2}}(a+b+c)} , area T...

= 1 2 ( a + b + c ) {\displaystyle s={\tfrac {1}{2}}(a+b+c)} is the semiperimeter. The tangency points of the incircle divide the sides into segments...

perimeter into two equal lengths, this common length being called the semiperimeter of the triangle. The three splitters of a triangle all intersect each...

( a + b + c + d ) {\displaystyle s={\tfrac {1}{2}}(a+b+c+d)} is the semiperimeter of the trapezoid. (This formula is similar to Brahmagupta's formula...

d ) {\displaystyle K={\sqrt {(s-a)(s-b)(s-c)(s-d)}}\,} where s, the semiperimeter, is s = ⁠1/2⁠(a + b + c + d). This is a corollary of Bretschneider's...

(orig. 1960). Gutierrez, Antonio, "Hexagon, Inscribed Circle, Tangent, Semiperimeter", [1] Archived 2012-05-11 at the Wayback Machine, Accessed 2012-04-17...

q: K = p ⋅ q 2 , {\displaystyle K={\frac {p\cdot q}{2}},} or as the semiperimeter times the radius of the circle inscribed in the rhombus (inradius):...

= 1 2 ( a + b + c ) {\displaystyle s={\tfrac {1}{2}}(a+b+c)} be the semiperimeter, T = s ( s − a ) ( s − b ) ( s − c ) . {\displaystyle T={\sqrt {s(s-a)(s-b)(s-c)}}...

The parameters in a triangle inequality can be the side lengths, the semiperimeter, the angle measures, the values of trigonometric functions of those...

where the sides in sequence are a, b, c, d, where s is the semiperimeter, and A and C are two (in fact, any two) opposite angles. This reduces...

, R ( z ) {\displaystyle R(z),R(z)} and l 1 {\displaystyle l_{1}} (semiperimeter R ( z ) + l 1 ( z ) / 2 {\displaystyle R(z)+l_{1}(z)/2} ) plus n {\displaystyle...

tangential quadrilateral add up to the same total length, which equals the semiperimeter s of the quadrilateral: a + c = b + d = a + b + c + d 2 = s . {\displaystyle...

inequality holding for an obtuse triangle. For an acute triangle with semiperimeter s,: p.115, #2874  s − r > 2 R , {\displaystyle s-r>2R,} and the reverse...

s = 1 2 ( a + b + c ) {\textstyle s={\tfrac {1}{2}}(a+b+c)} is the semiperimeter, or half of the triangle's perimeter. Three other equivalent ways of...

b,c)<a+b+c} and thus that the longest side length is less than the semiperimeter. A mathematically equivalent formulation is that the area of a triangle...

radius of the outer Soddy circle of any right triangle is equal to its semiperimeter. The outer Soddy center is located at D, where ACBD is a rectangle,...

In the earliest usages, the Greek letter π was used to denote the semiperimeter (semiperipheria in Latin) of a circle and was combined in ratios with...

Nagel point intersection of lines from each vertex to the corresponding semiperimeter point X(9) Mittenpunkt symmedian point of the triangle formed by the...

coordinate system Pole Real axis Secant line Circular sector or "sector" Semiperimeter Symmetry Shape Pattern Crystal system Frieze group Isometry Lattice...

{A-B}{2}}}{\tan {\frac {A+B}{2}}}}={\frac {a-b}{a+b}}} . If s is the triangle's semiperimeter, (a + b + c)/2, and r is the radius of the triangle's incircle, then...

\textstyle k={\sqrt {s(s-a)(s-b)(s-c)}}} , where s {\displaystyle s} is the semiperimeter – was known to Archimedes several centuries before Heron lived. Arabic...

)]}}.} Here, a, b, c, d are the sides of the quadrilateral, s is the semiperimeter, and α and γ are any two opposite angles, since cos ⁡ ( α + γ ) = cos...

the given triangle. The perimeter of the medial triangle equals the semiperimeter (half the perimeter) of the original triangle, and its area is one quarter...

line segment from the orthocenter to the circumcenter as e, and the semiperimeter as s, the following inequalities hold: d s < d u < d v < 1 3 ; {\displaystyle...

+ c {\displaystyle d={\frac {2{\sqrt {bcs(s-a)}}}{b+c}}} where the semiperimeter s = a + b + c 2 . {\displaystyle s={\tfrac {a+b+c}{2}}.} The side of...

lengths of opposite sides are the same. Both sums of lengths equal the semiperimeter of the quadrilateral. The converse implication is also true: whenever...

side lengths of a triangle are a , b , c {\displaystyle a,b,c} , the semiperimeter s = ( a + b + c ) / 2 , {\displaystyle s=(a+b+c)/2,} and A is the angle...