• Thumbnail for P–n junction
    of positively-charged donor atoms. Let N 0 ( x ) {\displaystyle N_{0}(x)} and P 0 ( x ) {\displaystyle P_{0}(x)} be the equilibrium concentrations of...
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  • x 1 ) ( x 0 − x 2 ) ⋯ ( x 0 − x n ) y 0 + ( xx 0 ) ( xx 2 ) ⋯ ( xx n ) ( x 1 − x 0 ) ( x 1 − x 2 ) ⋯ ( x 1 − x n ) y 1 + ⋯ + ( xx 0 ) ( x...
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  • Thumbnail for Gradient
    f\colon \mathbb {R} ^{n}\to \mathbb {R} ^{n}} is defined at the point p = ( x 1 , … , x n ) {\displaystyle p=(x_{1},\ldots ,x_{n})} in n-dimensional space...
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  • Thumbnail for Pięć Dwa
    hiphopedia.info. Retrieved 2014-06-15. "52 Dębiec - P-ń VI" (in Polish). hiphopedia.info. Retrieved 2014-06-15. "P-Ń Vi Pięć Dwa Dębiec". itunes.apple.com. Retrieved...
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  • Thumbnail for Geometric distribution
    ( X ) = p E [ X | X = 1 ] + ( 1 − p ) E [ X | X > 1 ] = p E [ X | X = 1 ] + ( 1 − p ) ( 1 + E [ X − 1 | X > 1 ] ) = p ⋅ 1 + ( 1 − p ) ⋅ ( 1 + E [ X ]...
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  • q n ( x ⌣ y ) = ∑ i + j = n ( S q i x ) ⌣ ( S q j y ) or P n ( x ⌣ y ) = ∑ i + j = n ( P i x ) ⌣ ( P j y ) {\displaystyle {\begin{aligned}Sq^{n}(x\smile...
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  • Thumbnail for Legendre polynomials
    recursion formula ( n + 1 ) P n + 1 ( x ) = ( 2 n + 1 ) x P n ( x ) − n P n − 1 ( x ) . {\displaystyle (n+1)P_{n+1}(x)=(2n+1)xP_{n}(x)-nP_{n-1}(x)\,.} This relation...
    31 KB (5,552 words) - 07:39, 2 October 2024
  • x ) {\displaystyle f(x)} is J n { f ( x ) } = f ~ ( n ) = ∫ − 1 1 P n ( x )   f ( x )   d x {\displaystyle {\mathcal {J}}_{n}\{f(x)\}={\tilde {f}}(n)=\int...
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  • p = X / Y. "X to Y in favor" means that the probability is p = X / (X + Y). "X to Y against" means that the probability is p = Y / (X + Y). "pays X to...
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  • Thumbnail for Gaussian quadrature
    x ) x k p n ( x ) xx i d x = x i k ∫ a b ω ( x ) p n ( x ) xx i d x {\displaystyle \int _{a}^{b}\omega (x){\frac {x^{k}p_{n}(x)}{x-x_{i}}}dx=x_{i}^{k}\int...
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  • Add N to (X) were an English electronic music band formed in London in 1994. The original members were Andrew Aveling, Barry Smith (aka Barry 7) and Ann...
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  • Contents:  A–L (previous page) M N O P Q R S T U V W X Y Z See also References Mary MacPherran (portrayed by Jameela Jamil), also known as Titania, is...
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  • expenditure x 1 p 1 + ⋯ + x n p n {\displaystyle x_{1}p_{1}+\dots +x_{n}p_{n}} subject to the minimal utility constraint that u ( x 1 , … , x n ) ≥ u ∗ ...
    8 KB (1,665 words) - 14:20, 17 October 2023
  • for glossaries of specific fields of engineering. Contents:  M N O P Q R S T U V W X-Z See also References External links Macaulay's method (The double...
    250 KB (31,103 words) - 16:47, 10 September 2024
  • specifically, f ( x ) = f ( x 1 , … , x n ) = ∑ q = 0 2 n Φ q ( ∑ p = 1 n ϕ q , p ( x p ) ) {\displaystyle f(\mathbf {x} )=f(x_{1},\ldots ,x_{n})=\sum _{q=0}^{2n}\Phi...
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  • solute: p = p A ⋆ x A , {\displaystyle p=p_{\text{A}}^{\star }x_{\text{A}},} Δ p = p A ⋆ − p = p A ⋆ ( 1 − x A ) = p A ⋆ x B . {\displaystyle \Delta p=p_{\text{A}}^{\star...
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  • modulo p {\displaystyle p} as: f p ( x ) = ∑ n = 0 ∞ f ( p n ) x n . {\displaystyle f_{p}(x)=\sum _{n=0}^{\infty }f(p^{n})x^{n}.} Two multiplicative functions...
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  • sequence { p n ( x ) } n = 0 , 1 , 2 , … {\displaystyle \{p_{n}(x)\}_{n=0,1,2,\ldots }} satisfying the identity d d x p n ( x ) = n p n − 1 ( x ) , {\displaystyle...
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  • or p/q theorem) states a constraint on rational solutions of a polynomial equation a n x n + a n − 1 x n − 1 + ⋯ + a 0 = 0 {\displaystyle a_{n}x^{n...
    10 KB (1,508 words) - 21:10, 26 September 2024
  • polynomial p ( x ) = ∑ i = 0 n a i x i = a 0 + a 1 x + a 2 x 2 + a 3 x 3 + ⋯ + a n x n , {\displaystyle p(x)=\sum _{i=0}^{n}a_{i}x^{i}=a_{0}+a_{1}x+a_{2}x^{2}+a_{3}x^{3}+\cdots...
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  • 1 n | x k + y k | p ) 1 / p ≤ ( ∑ k = 1 n | x k | p ) 1 / p + ( ∑ k = 1 n | y k | p ) 1 / p {\displaystyle {\biggl (}\sum _{k=1}^{n}|x_{k}+y_{k}|^{p}{\biggr...
    10 KB (2,047 words) - 18:15, 3 July 2024
  • D KL ( P ∥ Q ) = ∑ xX P ( x )   log ⁡ (   P ( x )   Q ( x ) ) . {\displaystyle D_{\text{KL}}(P\parallel Q)=\sum _{x\in {\mathcal {X}}}P(x)\ \log \left({\frac...
    73 KB (12,462 words) - 20:39, 2 October 2024
  • connected with diabetes. Contents:  Top A B C D E F G H I J K L M N O P R S T U V X References Acanthosis nigricans A brown to black, poorly defined,...
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  • identities p n ( x + y ) = ∑ k = 0 n ( n k ) p k ( x ) p n − k ( y ) . {\displaystyle p_{n}(x+y)=\sum _{k=0}^{n}{n \choose k}\,p_{k}(x)\,p_{n-k}(y).} Many...
    12 KB (2,069 words) - 20:33, 26 November 2023
  • Ultimate Marvel characters. Contents A B C D E F G H I J K L M N O P Q R S T U V W X Y Z Ant Man Abomination (Lam, Chang) Abraham Cornelius Abraham Erskine...
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  • Thumbnail for Central limit theorem
    be stated as: let X 1 , X 2 , … , X n {\displaystyle X_{1},X_{2},\dots ,X_{n}} denote a statistical sample of size n {\displaystyle n} from a population...
    65 KB (8,861 words) - 09:47, 3 October 2024
  • secondary polynomials { q n ( x ) } {\displaystyle \{q_{n}(x)\}} associated with a sequence { p n ( x ) } {\displaystyle \{p_{n}(x)\}} of polynomials orthogonal...
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  • Thumbnail for Bertrand's postulate
    p n {\displaystyle p_{n}} is the n {\displaystyle n} -th prime, is: for n ≥ 1 {\displaystyle n\geq 1} p n + 1 < 2 p n . {\displaystyle p_{n+1}<2p_{n}...
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  • Thumbnail for Binomial coefficient
    = ( 4 0 ) x 0 + ( 4 1 ) x 1 + ( 4 2 ) x 2 + ( 4 3 ) x 3 + ( 4 4 ) x 4 = 1 + 4 x + 6 x 2 + 4 x 3 + x 4 , {\displaystyle {\begin{aligned}(1+x)^{4}&={\tbinom...
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  • as P n ( x ; c ; q ) = 3 ϕ 2 ( q − n , q n + 1 , x ; q , c q ; q , q ) {\displaystyle \displaystyle P_{n}(x;c;q)={}_{3}\phi _{2}(q^{-n},q^{n+1},x;q,cq;q...
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