{\displaystyle {\frac {v^{2}}{2}}+\left({\frac {\gamma }{\gamma -1}}\right){\frac {p}{\rho }}=\left({\frac {\gamma }{\gamma -1}}\right){\frac {p_{0}}{\rho...

Δ t = s ( t 1 ) − s ( t 0 ) t 1 − t 0 . {\displaystyle {\frac {\Delta s}{\Delta t}}={\frac {s(t_{1})-s(t_{0})}{t_{1}-t_{0}}}.} Here, the Greek letter...

terminal velocity is given by V t = 2 m g ρ A C d {\displaystyle V_{t}={\sqrt {\frac {2mg}{\rho AC_{d}}}}} where V t {\displaystyle V_{t}} represents terminal...

d W d t d R d t = − F V , {\displaystyle {\frac {dW}{dR}}={\frac {\frac {dW}{dt}}{\frac {dR}{dt}}}=-{\frac {F}{V}},} where V {\displaystyle V} is the...

{\displaystyle {\frac {{\frac {L_{p}}{A}}{\frac {N_{r}}{C}}-{\frac {N_{p}}{C}}{\frac {L_{r}}{A}}}{{\frac {N_{p}}{C}}{\frac {E}{A}}-{\frac {L_{p}}{A}}}}}...

physicist and philosopher Ernst Mach. M = u c , {\displaystyle \mathrm {M} ={\frac {u}{c}},} where: M is the local Mach number, u is the local flow velocity...

{\displaystyle {\frac {L}{r^{2}}}{\frac {d}{d\theta }}\left({\frac {L}{mr^{2}}}{\frac {dr}{d\theta }}\right)-{\frac {L^{2}}{mr^{3}}}=-{\frac {dV}{dr}}.} This...

distributed by the flywheel is therefore: K E fly = η fly m v 2 2 {\displaystyle KE_{\text{fly}}={\frac {\eta _{\text{fly}}mv^{2}}{2}}} Regenerative braking has...

frac {V+c_{m}'}{1+{\frac {Vc_{m}'}{c^{2}}}}}={\frac {V+{\frac {c}{n}}}{1+{\frac {Vc}{nc^{2}}}}}={\frac {c}{n}}{\frac {1+{\frac {nV}{c}}}{1+{\frac {V}{nc}}}}\\&={\frac...

dS={\frac {1}{T}}\sum _{j}E_{j}dP_{j}={\frac {1}{T}}\sum _{j}d\left(E_{j}P_{j}\right)-{\frac {1}{T}}\sum _{j}P_{j}dE_{j}={\frac {dE+\delta W}{T}}={\frac {\delta...

{\displaystyle {\begin{aligned}{\frac {\partial {\mathcal {E}}}{\partial x_{\ell }}}&={\frac {\partial {\mathcal {E}}}{\partial x_{L}}}{\frac {\partial x_{L}}{\partial...

}={\frac {t_{a}-{\frac {vx_{a}}{c^{2}}}}{\sqrt {1-{\frac {v^{2}}{c^{2}}}}}},\ t_{b}^{\prime }={\frac {t_{b}-{\frac {vx_{b}}{c^{2}}}}{\sqrt {1-{\frac {v^{2}}{c^{2}}}}}}}...

− 3 2 R + b 2 2 R 3 ) {\displaystyle {\frac {1}{2}}mv^{2}=NeE\cdot \left({\frac {1}{b}}-{\frac {3}{2R}}+{\frac {b^{2}}{2R^{3}}}\right)} In Rutherford's...

mathematically: A 2 = A 1 ( ℓ 2 ℓ 1 ) 2 {\displaystyle A_{2}=A_{1}\left({\frac {\ell _{2}}{\ell _{1}}}\right)^{2}} where A 1 {\displaystyle A_{1}} is the...

2 , {\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}=\left({\frac {F_{\text{P}}l_{\text{P}}^{2}}{m_{\text{P}}^{2}}}\right){\frac {m_{1}m_{2}}{r^{2}}},} can...

\over R_{1}}\cdot ln{\left({1 \over {{\frac {V_{CC}}{V_{D}}}+1}}\right)}={L \over R_{1}}\cdot ln{\left({{\frac {V_{CC}}{V_{D}}}+1}\right)}} Flyback diodes...

\left({\frac {\xi }{\xi _{\mathrm {cutoff} }}}\right)={\frac {2}{\pi }}\left\{\cos ^{-1}\left({\frac {\xi }{\xi _{\mathrm {cutoff} }}}\right)-\left({\frac {\xi...

stored by the flywheel's rotor can be calculated by 1 2 I ω 2 {\textstyle {\frac {1}{2}}I\omega ^{2}} . ω is the angular velocity, and I {\displaystyle I}...

as a phrase to warn of the coming of the police (typically "22, v'là les flics !" (In English: "5-0! Cops!") In photography, f/22 is the largest f-stop...

u_{\alpha }^{}={\frac {(1-\alpha ){\frac {u_{0}}{z_{0}}}+\alpha {\frac {u_{1}}{z_{1}}}}{(1-\alpha ){\frac {1}{z_{0}}}+\alpha {\frac {1}{z_{1}}}}}} 3D...

S = C L 2 π A R e {\displaystyle C_{D,i}={\frac {D_{\text{i}}}{{\frac {1}{2}}\rho _{0}V_{E}^{2}S}}={\frac {C_{L}^{2}}{\pi A\!\!{\text{R}}e}}} , where...

i\approx -{\frac {2\rho }{3J_{2}R_{\text{E}}^{2}{\sqrt {\mu }}}}a^{7/2}=-\left({\frac {a}{12\,352{\text{ km}}}}\right)^{7/2}=-\left({\frac {T}{3.795{\text{...

x ) 2 = 1 2 m i u 0 2 − e φ ( x ) {\displaystyle {\frac {1}{2}}m_{\mathrm {i} }\,u(x)^{2}={\frac {1}{2}}m_{\mathrm {i} }\,u_{0}^{2}-e\,\varphi (x)} ...

{\displaystyle F_{x}={\frac {B_{r}V_{m}I}{2\pi }}{\frac {\partial }{\partial x}}\left({\frac {x-\Delta x_{0}}{(x-\Delta x_{0})^{2}+d^{2}}}+{\frac {x+\Delta x_{0}}{(x+\Delta...

{\displaystyle \left({{\frac {1}{3}}+{\frac {1}{5}}}\right)+\left({{\frac {1}{5}}+{\frac {1}{7}}}\right)+\left({{\frac {1}{11}}+{\frac {1}{13}}}\right)+\cdots...

Q={\begin{pmatrix}-1&{\frac {1}{2}}&&{\frac {1}{2}}\\{\frac {1}{4}}&-1&{\frac {1}{4}}&&{\frac {1}{4}}&&&{\frac {1}{4}}\\&{\frac {1}{2}}&-1&&&{\frac {1}{2}}\\{\frac {1}{3}}&&&-1&{\frac...

max = 1 2 π ε AR C D , 0 , {\displaystyle (L/D)_{\text{max}}={\frac {1}{2}}{\sqrt {\frac {\pi \varepsilon {\text{AR}}}{C_{D,0}}}},} where AR is the aspect...

{\displaystyle u={\sqrt {{\frac {2\gamma }{\gamma -1}}{\frac {p_{s}}{\rho }}\left[\left({\frac {p_{t}}{p_{s}}}\right)^{\frac {\gamma -1}{\gamma }}-1\right]}}}...

+ 1 1 + k p k c τ p s + 1 {\displaystyle g_{CL}={\frac {\frac {k_{p}k_{c}}{\tau _{p}s+1}}{1+{\frac {k_{p}k_{c}}{\tau _{p}s+1}}}}} . Simplifying this equation...

{\text{DA}}\approx {\frac {T_{\text{SL}}}{\Gamma }}\left[1-\left({\frac {P/P_{\text{SL}}}{T/T_{\text{SL}}}}\right)^{\left({\frac {gM}{\Gamma R}}-1\right)^{-1}}\right]...