1856 United States presidential election in Arkansas

The 1856 United States presidential election in Arkansas was held on November 4, 1856. Arkansas voters chose four electors to represent the state in the Electoral College, which chose the president and vice president.

Arkansas voted for the Democratic nominee James Buchanan, who received 67% of the vote.^[1]

Republican Party nominee John C. Frémont was not on the ballot.

Results

1856 United States presidential election in Arkansas
Party		Candidate	Votes	%
	Democratic	James Buchanan	21,910	67.12%
	Know Nothing	Millard Fillmore	10,732	32.88%
Total votes			32,642	100%

References

^ "1856 Presidential General Election Results - Arkansas". David Leip's U.S. Election Atlas. Retrieved 2017-06-05.

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[1] "1856 Presidential General Election Results - Arkansas". David Leip's U.S. Election Atlas. Retrieved 2017-06-05.

[1]

v t e Elections in Arkansas
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U.S. Senate	Class 2: 1833 1839–40 1848 S 1853 1859 1868 S 1870 1876 1883 1885 S 1889 1895 1901 1907 1913 S 1913 1918 1924 1930 1936 1937 S 1942 1948 1954 1960 1966 1972 1978 1984 1990 1996 2002 2008 2014 2020 Class 3: 1837 1843 1845 S 1849 1855 1861 1867 1873 1879 1881 S 1885 1891 1897 1903 1909 1914 1916 S 1920 1926 1932 S 1932 1938 1944 1950 1956 1962 1968 1974 1980 1986 1992 1998 2004 2010 2016 2022
U.S. House	1837 1838 1840 1842 1844 1846 1848 1851 1853 1854 1856 1858 1860 1868 1870 1872 1874 1876 1878 1880 1882 1884 1886 1888 1890 1892 1894 1896 1898 1900 1902 1904 1906 1908 1910 1912 1914 1916 1918 1920 1922 1924 1926 1928 1930 1932 1934 1936 1938 1940 (4th S) 1942 1944 1946 1948 1950 1952 1954 1956 1958 1960 (6th S) 1962 1964 1966 (4th S) 1968 1970 1972 1974 1976 1978 1980 1982 1984 1986 1988 1990 1992 1994 1996 1998 2000 2002 2004 2006 2008 2010 2012 2014 2016 2018 2020 2022
'S,' denotes special election; 'U,' denotes election under Federal (Union) military occupation See also: Political party strength in Arkansas

1856 United States presidential election in Arkansas

Results

See also

References