1900 Tasmanian colonial election|
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The 1900 Tasmanian colonial election was held on 9 March 1900 in the Australian colony of Tasmania to elect 38 members of the Tasmanian House of Assembly.[citation needed]
The 1900 election was the second to use a limited version of the Hare-Clark system within Hobart and Launceston, which were given 6 and 4 seats respectively, while still using first past the post single-member constituencies elsewhere in the state. Following this term, the system largely returned to its pre–1897 state (all members elected through first past the post), but at the 1909 election, the entire State was redivided into five electorates using the Hare-Clark system.
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Party | Votes | % | Seats | +/– |
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| Free Trade | 5,134 | 27.20 | 18 | 1 |
| Protectionist | 2,218 | 11.75 | 9 | 3 |
| Others | 7,319 | 38.78 | 0 | 1 |
| Independents | 4,201 | 22.26 | 11 | 6 |
Total | 18,872 | 100.00 | 38 | – |
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Valid votes | 18,872 | 97.38 | |
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Invalid/blank votes | 508 | 2.62 | |
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Total votes | 19,380 | 100.00 | |
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Registered voters/turnout | 39,002 | 49.69 | |
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Source: UWA |
Popular vote | | | | Free Trade Party | | 27.20% | Protectionist Party | | 11.75% | Independents | | 22.26% | Others | | 38.78% | |
Seats | | | | Free Trade Party | | 47.37% | Protectionist Party | | 23.68% | Independents | | 28.95% | |