1998 Florida Attorney General election

1998 Florida Attorney General election

← 1994 November 3, 1998 2002 →
 
Nominee Bob Butterworth David H. Bludworth
Party Democratic Republican
Popular vote 2,301,328 1,562,269
Percentage 59.6% 40.4%

Butterworth:      50–60%      60–70%      70–80%      80–90%      >90%
Bludworth:      50–60%      60–70%      70–80%      80–90%      >90%
Tie:      40–50%      50%      No votes

Attorney General before election

Bob Butterworth
Democratic

Elected Attorney General

Bob Butterworth
Democratic

The 1998 Florida Attorney General election was held on November 3, 1998. Democratic incumbent Bob Butterworth defeated Republican nominee David H. Bludworth with 59.56% of the vote. As of 2024, this was the last time a Democrat was elected Florida Attorney General.

Primary elections

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Primary elections were held on September 1, 1998.[1]

Democratic primary

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Candidates

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Results

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Democratic primary results[1]
Party Candidate Votes %
Democratic Bob Butterworth 475,757 81.80
Democratic Ellis Rubin 105,865 18.20
Total votes 581,622 100.00

Republican primary

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Republican Primary results by county:
  Bludworth
  •   50–60%
  •   60–70%
  •   70–80%
  Dudley
  •   50–60%
  •   60–70%
  •   70–80%

Candidates

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Results

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Republican primary results[1]
Party Candidate Votes %
Republican David H. Bludworth 298,375 53.89
Republican Fred Dudley 255,274 46.11
Total votes 553,649 100.00

General election

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Candidates

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  • Bob Butterworth, Democratic
  • David H. Bludworth, Republican

Results

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1998 Florida Attorney General election[2]
Party Candidate Votes % ±%
Democratic Bob Butterworth 2,301,328 59.56%
Republican David H. Bludworth 1,562,269 40.44%
Majority 739,059
Turnout
Democratic hold Swing

References

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  1. ^ a b c "September 1, 1998 Primary Election". Secretary of State of Florida. 1998. Retrieved June 1, 2021.
  2. ^ "November 3, 1998 General Election". Secretary of State of Florida. 1998. Retrieved June 1, 2021.