1804 Delaware gubernatorial election

1804 Delaware gubernatorial election

← 1801 October 2, 1804 1807 →
 
Nominee Nathaniel Mitchell Joseph Haslet
Party Federalist Democratic-Republican
Popular vote 4,391 4,050
Percentage 52.02% 47.98%

Mitchell:      50–60%      60–70%
Haslet:      60–70%

Governor before election

David Hall
Democratic-Republican

Elected Governor

Nathaniel Mitchell
Federalist

The 1804 Delaware gubernatorial election was held on October 2, 1804.

Incumbent Democratic-Republican Governor David Hall was not eligible for re-election under the Delaware Constitution of 1792.

Federalist nominee Nathaniel Mitchell defeated Democratic-Republican nominee Joseph Haslet with 52.02% of the vote.

General election

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Results

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1804 Delaware gubernatorial election[1][2][3][4]
Party Candidate Votes % ±%
Federalist Nathaniel Mitchell 4,391 52.02%
Democratic-Republican Joseph Haslet 4,050 47.98%
Majority 341 4.04%
Turnout 8,441 100.00%
Federalist gain from Democratic-Republican Swing

References

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  1. ^ "DE Governor, 1804". Our Campaigns. Retrieved December 8, 2020.
  2. ^ Congressional Quarterly 1998, p. 46.
  3. ^ Glashan 1979, pp. 50–51.
  4. ^ Dubin 2003, p. 26.

Bibliography

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  • Gubernatorial Elections, 1787-1997. Washington, D.C.: Congressional Quarterly Inc. 1998. ISBN 1-56802-396-0.
  • Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Meckler Books. ISBN 0-930466-17-9.
  • Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson, North Carolina: McFarland. ISBN 978-0-7864-1439-0.