1824 New Hampshire gubernatorial election

1824 New Hampshire gubernatorial election

← 1823 9 March 1824 1825 →
 
Nominee David L. Morril Levi Woodbury Jeremiah Smith
Party Democratic-Republican Democratic-Republican Federalist
Popular vote 14,985 11,741 3,300
Percentage 49.19% 38.54% 10.83%

County results
Morril:      40–50%      50–60%      60–70%
Woodbury:      50–60%      60–70%

Governor before election

Levi Woodbury
Democratic-Republican

Elected Governor

David L. Morril
Democratic-Republican

The 1824 New Hampshire gubernatorial election was held on 9 March 1824 in order to elect the governor of New Hampshire. Former Democratic-Republican United States senator from New Hampshire David L. Morril defeated incumbent Democratic-Republican governor Levi Woodbury and former Federalist governor Jeremiah Smith. Since no candidate received a majority in the popular vote, Morril was elected by the New Hampshire General Court per the state constitution.[1]

General election

[edit]

On election day, 9 March 1824, Democratic-Republican candidate David L. Morril won the popular vote by a margin of 3,244 votes against his foremost opponent and incumbent Democratic-Republican governor Levi Woodbury. But since no candidate received a majority of the popular vote, a separate election was held by the New Hampshire General Court, which chose Morril as the winner, thereby retaining Democratic-Republican control over the office of governor. Morril was sworn in as the 10th governor of New Hampshire on 2 June 1824.[2]

Results

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New Hampshire gubernatorial election, 1824
Party Candidate Votes %
Democratic-Republican David L. Morril 14,985 49.19
Democratic-Republican Levi Woodbury (incumbent) 11,741 38.54
Federalist Jeremiah Smith 3,300 10.83
Scattering 438 1.44
Total votes 30,464 100.00
Democratic-Republican hold

References

[edit]
  1. ^ "David L. Morril". National Governors Association. Retrieved 1 April 2024.
  2. ^ "NH Governor". ourcampaigns.com. 2 June 2005. Retrieved 1 April 2024.