1832 United States presidential election in Indiana
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Elections in Indiana |
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The 1832 United States presidential election in Indiana took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.
Indiana voted for the Democratic Party candidate, Andrew Jackson, over the National Republican candidate, Henry Clay. Jackson won Indiana by a margin of 34.20%.
As of 2020, this remains the strongest performance by a Democrat in Indiana.[1]
Results
[edit]1832 United States presidential election in Indiana[2] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Andrew Jackson (incumbent) | 31,551 | 67.10% | 9 | |
National Republican | Henry Clay | 15,472 | 32.90% | 0 | |
Totals | 47,023 | 100.0% | 9 |
See also
[edit]References
[edit]- ^ "Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved January 10, 2023.
- ^ "1832 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved April 12, 2013.