1840 United States presidential election in Massachusetts

1840 United States presidential election in Massachusetts

← 1836 November 9, 1840 1844 →
← MD
DE →
Turnout66.7%[1] Increase 23.3 pp
 
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote 14 0
Popular vote 72,852 52,355
Percentage 57.44% 41.28%

County Results

President before election

Martin Van Buren
Democratic

Elected President

William Henry Harrison
Whig

A presidential election was held in Massachusetts on November 9, 1840 as part of the 1840 United States presidential election.[2] Voters chose 14 representatives, or electors to the Electoral College, who voted for President and Vice President.

Massachusetts voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Massachusetts by a margin of 16.16%.

Results

[edit]
1840 United States presidential election in Massachusetts[3]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Whig William Henry Harrison of Ohio John Tyler of Virginia 72,852 57.44% 14 100.00%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 52,355 41.28% 0 0.00%
Liberty James G. Birney of New York Thomas Earle of Pennsylvania 1,618 1.28% 0 0.00%
Total 126,825 100.00% 14 100.00%

See also

[edit]

References

[edit]
  1. ^ Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
  2. ^ Dubin, Michael J. (2002). United States Presidential Elections, 1788–1860: The Official Results by County and State. Jefferson, NC: McFarland & Co. p. xvi.
  3. ^ "1840 Presidential General Election Results – Massachusetts". U.S. Election Atlas. Retrieved December 23, 2013.