1890 Kansas gubernatorial election

1890 Kansas gubernatorial election

← 1888 November 4, 1890 1892 →
 
Nominee Lyman U. Humphrey John F. Willits Charles L. Robinson
Party Republican Populist Democratic
Popular vote 115,024 106,945 71,357
Percentage 39.05% 36.31% 24.23%

County results
Humphrey:      30–40%      40–50%      50–60%      60–70%
Willits:      30–40%      40–50%      50–60%
Robinson:      30–40%      40–50%      50–60%      60–70%

Governor before election

Lyman U. Humphrey
Republican

Elected Governor

Lyman U. Humphrey
Republican

The 1890 Kansas gubernatorial election was held on November 4, 1890. Incumbent Republican Lyman U. Humphrey defeated People's Party nominee John F. Willits with 39.05% of the vote.

General election

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Candidates

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Major party candidates

  • Lyman U. Humphrey, Republican
  • Charles L. Robinson, Democratic

Other candidates

  • John F. Willits, People's
  • A. M. Richardson, Prohibition

Results

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1890 Kansas gubernatorial election[1]
Party Candidate Votes % ±%
Republican Lyman U. Humphrey (incumbent) 115,024 39.05%
Populist John F. Willits 106,945 36.31%
Democratic Charles L. Robinson 71,357 24.23%
Prohibition A. M. Richardson 1,230 0.42%
Majority 8,079
Turnout
Republican hold Swing

References

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  1. ^ Guide to U.S. elections - CQ Press, Congressional Quarterly, inc. CQ Press. 2005. ISBN 9781568029818. Retrieved July 5, 2020.