1940 Iowa gubernatorial election

1940 Iowa gubernatorial election

← 1938 November 7, 1940 1942 →
 
Nominee George A. Wilson John K. Valentine
Party Republican Democratic
Popular vote 620,480 553,941
Percentage 52.72% 47.07%

County results
Wilson:      40–50%      50–60%      60–70%
Valentine:      50–60%

Governor before election

George A. Wilson
Republican

Elected Governor

George A. Wilson
Republican

The 1940 Iowa gubernatorial election was held on November 5, 1940. Incumbent Republican George A. Wilson defeated Democratic nominee John K. Valentine with 52.72% of the vote.

Primary elections

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Primary elections were held on June 3, 1940.[1]

Democratic primary

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Candidates

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Results

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Democratic primary results[1]
Party Candidate Votes %
Democratic John K. Valentine 70,233 57.88
Democratic Edward Breen 51,112 42.12
Total votes 121,345 100.00

Republican primary

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Candidates

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Results

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Republican primary results[1]
Party Candidate Votes %
Republican George A. Wilson (incumbent) 165,176 49.66
Republican H. R. Gross 146,395 44.01
Republican Irving H. Knudson 21,039 6.33
Total votes 332,610 100.00

General election

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Candidates

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Major party candidates

  • George A. Wilson, Republican
  • John K. Valentine, Democratic

Other candidates

  • M. M. Heptonstall, Prohibition
  • Charles Speck, Communist

Results

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1940 Iowa gubernatorial election[2]
Party Candidate Votes % ±%
Republican George A. Wilson (incumbent) 620,480 52.72%
Democratic John K. Valentine 553,941 47.07%
Prohibition M. M. Heptonstall 1,289 0.11%
Communist Charles Speck 1,230 0.11%
Majority 66,539
Turnout
Republican hold Swing

References

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  1. ^ a b c "Summary of Official Canvass of Votes Cast in Iowa Primary Election" (PDF). Secretary of State of Iowa. 1940. Retrieved April 18, 2020.
  2. ^ "Summary of Official Canvass of Votes Cast in Iowa General Election" (PDF). Secretary of State of Iowa. 1940. Retrieved April 18, 2020.