1895 Rhode Island gubernatorial election
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County results Lippitt: 50–60% 60–70% | |||||||||||||||||||||
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Elections in Rhode Island |
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The 1895 Rhode Island gubernatorial election was held on April 3, 1895. Republican nominee Charles W. Lippitt defeated Democratic nominee George L. Littlefield with 56.89% of the vote.
General election
[edit]Candidates
[edit]Major party candidates
- Charles W. Lippitt, Republican
- George L. Littlefield, Democratic
Other candidates
- Smith Quimby, Prohibition
- George Boomer, Socialist Labor
- William Foster Jr., People's
Results
[edit]Party | Candidate | Votes | % | ±% | |
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Republican | Charles W. Lippitt | 25,098 | 56.89% | ||
Democratic | George L. Littlefield | 14,289 | 32.39% | ||
Prohibition | Smith Quimby | 2,624 | 5.95% | ||
Socialist Labor | George Boomer | 1,730 | 3.92% | ||
Populist | William Foster Jr. | 379 | 0.86% | ||
Majority | 10,809 | ||||
Turnout | |||||
Republican hold | Swing |
References
[edit]- ^ Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved July 18, 2020.